Exercícios de estatística

Álgebra Linear

Engenharia elétrica
Johnatas Cruz 2163249518
Turma A
Nos problemas de 1 a 3, calcular os valores de m e n para que as matrizes A e B sejam iguais. 1- A=815n12+m3 e B = 87563

15n=75 n=7515 n=5 12+m=6 m=6-12 n=-6

2- A=m2-40n2+463 e B = 411363

m2-40=41 m2=81 m=81 m=9

n2+4=13 n2=9 n=9 n=3

3- A=784x2 e B = 78410x-25

x2=10x-25 x2-10x+25=0

x=-(-10)±102-4.1.252.1 x=10±02 x=5

Dada as matrizes
A2384-1-6, B5-7-9041e C098146

4- Calcular A + B.
A2384-1-6+ B5-7-9041=7-4-143-5

5- Calcular B + C.
B5-7-9041+ C098146=52-1187

6- Calcular A + C.
A2384-1-6+C098146=21216530

7- Calcular A - B.

A2384-1-6- B5-7-9041=-310174-5-7

8- Calcular B - C.
B5-7-9041- C098146=5-16-17-10-5

9- Calcular A - C.
A2384-1-6-C098146=2-603-5-12

10- Calcule X = 4A – 3B + 5C

X=4.24.34.84.44.(-1)4.(-6)- 3.53.(-7)3.(-9)3.03.43.1+5.05.95.85.15.45.6

X= 8123216-4-24-15-21-270123+0454052030

X=-7335916-16-27+0454052030

X=-778992143

11- Calcule X = 2B – 3A – 6C

X= 10-14-18082-692412-3-18-0544862436

X=4-23-42-121120-0544862436

X=4-77-90-18-1316

12- Calcule X = 4C + 2A – 6B

X= 0363241624+46168-2-12-30-42-540246

X=44248121412-30-42-540246

X=-268410212-106

Nos problemas 13 a 15, efetua a multiplicação das matrizes A e X.

13- A=26-54 e X=xy AX=2x6y-5x4y

14- A=123-2-5739-8e X=x1x2x3 AX=1x12x23x3-2x1-5x27x33x19x2-8x3

15- A=-3428013-6-245-79-9-86e X=x1x2x3x4 AX=-3x14x22x38x401x23x3-6x4-2x14x25x3-7x49x1-9x2-8x36x4

Dadas as matrizes

A=1-2317-459, B=13-5-762-83, C=24-35e D=173-8-3-1-1-34190532-3

16- AB =1-123-4-5+16-7-63+69+2-15-8-21+37-2421-8-35+32-49-125+5415+18-25-72-35+27

AB=-11-111-13911-23-18-1713-3-615933-97-8

17- (AB)D =-11-111-13911-23-18-1713-3-615933-97-8 x 173-8-3-1-1-34190532-3

(AB)D