# Estatística

Páginas: 5 (1048 palavras) Publicado: 6 de abril de 2013
Trabalho de Estatística

1) a) I) 12 4 h = 12+0,16 = 12h 9min 36seg
25

II) 8 7 h = 8+0,3181818 = 8h 19min 5seg
22

2) a) I) 542,55 = 543 II) 78,5 = 78

3) a) I) 8h 45min = 8 45 = 8 3 = 8,75 h
60 4

II) 15h 45seg = 15 45 = 15 1 h
3600 80

4) a) I) 8h + 36min = 8 36 = 83 h
60 5

II) 45min – 30seg = 45 - 36 = 3 - 1 = 90-1 = 89 h
60 3600 4 120 120 120

d) I) 21° 45’ 55’’ = 52’ 14’’
25
21 = 50’ 24’’
25
45 = 1’ 48’’
25
55 = 2’’
25

II) 49° 25’ 35’’ = 3° 17’ 42’’
15
49 = 3° 15’ 60’’
15
25 = 1’ 40’’
15
35 = 2’’
15g) III) 59 cm (0,001) = 59 = 0,055
108 dm 1080

5)
F Fa Fr Fra %fr %fra Ang. (°)
5 5 0,025 0,025 2,5 2,5 9
15 20 0,075 0,100 7,5 10,0 27
25 45 0,125 0,225 12,5 22,5 45
80 125 0,400 0,625 40,0 62,5 144
60 185 0,300 0,925 30,0 92,5 108
15 200 0,075 1,000 7,5 100,0 27
200 1,000 100,0 360

5 – 200 => x = 1800 => x = 9° 80 – 200 => x = 28800 => x = 144°x – 360 200 x – 360 200

15 – 200 => x = 5400 => x = 27° 60 – 200 => x = 21600 => x = 108°
x – 360 200 x – 360 200

25 – 200 => x = 9000 => x = 45° 15 – 200 => x = 5400 => x = 27°
x – 360 200 x – 360 200

Conjuntos

4) A= {7,0,9,8x} X = 8a

RolA = {0,7,8x,9} RolA = {0,7,9,16}

8 = 0,7,8x,9
4
32 = 16+8x
8x = 16a
x = 2a

Mo =Amodal
Md = 8a

8) A= {7,1,8,10x} Mo = 7h

RolA = {1,7,8,10x} 10x = 7
RolA = {1,7,7,8}

X = 1,7,7,8 => X = 5h 45min
4

Md = 7,7 = 7h
2

Tabelas

1) a) X = Σfx => X = 10320 => X 46a 10m 27d
Σf 220

b) Pmd = Σf = 220 = 110
2 2
Md = l + h(Pmd – faa) => Md = 45 + 10(110 – 70) => Md = 45 + (1100 + 700)
f 125 125
Md =45 + 400 => Md = 48a 2m 12d
125

c) Mo = l + hΔ1 => Mo = 45 + 10.80 => Mo = 45 + 855 => Mo = 49a 3m 10d
Δ1 + Δ2 80+107

d) Ppn = Σfn = 220.10 = 22
100 100
P10 = 25 + 10(22 – 5) => P10 = 25 + (220 – 50) => P10 = 25 + 8,5 => P10 = 33a 6m

e) Ppn = Σfn = 220.n = 2,2n
100 100

33,5 = 25 + 10(2,2n – 5) =>33,5 = 25 + (22n – 50) => 8,5 = 22n – 50 =>
20 20 20
8,5 = 1,1n – 2,5 => 1,1n = 11 => n = 11 => n = 10
1,1

f) Pqn = Σfn = 220.3 = 165
4 4
Q3 = 45 + 10(165 - 70) => Q3 = 45 + (1650 – 700) => Q3 = 45 + 7,6 =>
125 125
Q3 = 52a 7m 6d

g) Pdn = Σfn = 220.7 = 154
10 10
D7 = 45 + 10(154 –70) => D7 = 45 + (1540 – 700) => D7 = 45 + 6,72 =>
125 125
D7 = 51a 8m 19d

Medidas de dispersão

Custo (R\$) F Fa X Fx Fx²
20|-------40 40 40 30 1200 36000
40|-------60 100 140 50 5000 25000
60|-------80 60 200 70 4200 294000
∑ 200 10400 580000

a) AT= 80 – 20 = R\$ 60,00

b) Iq = Q3 – Q1 =
Pqn = Σfn = 200.3 = 150
4 4
Q3 = 60 +20(150 - 140) => Q3 = R\$ 63,33
60
Pqn = Σfn = 200.1 = 50
4 4
Q1 = 40 + 20(50 - 40) => Q1 = R\$ 42,00
60
Iq = 63,33 – 42,00 = R\$ 21,33

V= 1 ∑fx² - (∑fx)²
∑f-1 ∑f

V= 1 580000 - (10400)² = 196,99
199 200

S = V = R\$14,04

Apostila 2

1) a) E = {CC, CK, KC, KK} n(E) = 4
A = {KK} n(A) = 1
P(A) = n(A) = 1 = 25%
n(E) 4

b)B = {CK, KC} n(B) = 2
P(B) = n(B) = 2 = 50%
n(E) 4

2) a) A = {21,22,23 ... 200}
200 = 21 + (n-1) 1 => 179 = n-1 => n(E) = 180

B = {25,30,35 ... 200}
200 = 25 + (n-1) 5 => 175 = 5n – 5 => n = 180 => n(B) = 36...

Por favor, assinar para o acesso.