Eds unip

10

A = 2 3 B = 9 X = a 1 -3 6 b

A.X = B
2a 3b = 9
1a -3b 6

OBTEMOS O SISTEMA :
2a + 3b = 9 a - 3b = 6

RESOLVENDO 3a=15 portanto a=5
2.5 + 3b = 9 portanto b= -1/3

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11

A = 1 2 B = -3 8 C = y 9 -1 6 11 -12 1 x

A.C=B
1y + 2 9 + 2x = -3 8
-y + 6 -9 + 6x 11 -12

SISTEMAS: y+2 = -3 9+2x = 8
-y+6 = 11 -9+6x = -12

RESOLVENDO: y = -3-2 portanto y = -5
2x = 8-9 portanto x= -1/2

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12

I) VERDADEIRA

A+B = 2+1 4+5 = 1+2 5+4 = B+A -8-2 32+10 -2-8 10+32

II) FALSA

A.B = 2-8 10+40 = -6 50 -8-64 -40+320 -72 280

B.A = 2-40 4+160 = -38 164 -4-80 -8+320 -84 312

III) VERDADEIRA

2 (A+B) = 2.(2+1) 2.(4+5) = 6 18 2.(-8-2) 2.(32+10) -20 84

2A + 2B = 2.2+2.1 2.4+2.5 = 6 18 2.-8+2.-2 2.32+2.10 -20 84

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13

X = a b c d

(3A) – X = (2C) + B

(3.-4)-a (3.0)-b = (2.3)+5 (2.10)+8
(3.1)-c (3.-6)-d (2.-6)+1 (2.0)-2

-12-a 0-b = 11 28
3-c -18-d -11 -2

OBTEMOS O SISTEMA:
-12-a = 11 portanto a = -23
0-b = 28 portanto b = -28
3-c = -11 portanto c = 14
-18-d = -2 portanto d = -16

X = -23 -28 14