# Balanço

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• Publicado : 12 de outubro de 2011

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1)
A)

| |Fi |
|90|-100 |4 |
|80|-90 |7 |
|70|-80 |9 |
|60|-70 |11 |
|50|-60 |9 |
|40|-50 |6 |
|30|-40 |4 |
|Σ |50 |

b) 50

c)

| |Fi |fi |
|90|-100 |4 |0,08 ||80|-90 |7 |0,14 |
|70|-80 |9 |0,18 |
|60|-70 |11 |0,22 |
|50|-60 |9 |0,18 |
|40|-50 |6 |0,12 |
|30|-40 |4 |0,08 |
|Σ |50 |1 |

d)

| |Fi |Fac |
|30|-40 |4 |4|
|40|-50 |6 |10 |
|50|-60 |9 |19 |
|60|-70 |11 |30 |
|70|-80 |9 |39 |
|80|-90 |7 |46 |
|90|-100 |4 |50 |
|Σ |50 | |
| | | |

e)

| |Fi|fi |fiac |
|90|-100 |4 |0,08 |0,08 |
|80|-90 |7 |0,14 |0,22 |
|70|-80 |9 |0,18 |0,4 |
|60|-70 |11 |0,22 |0,62 |
|50|-60 |9 |0,18 |0,8 |
|40|-50 |6 |0,12 |0,92 |
|30|-40|4 |0,08 |1 |
|Σ |50 |1 | |

f)

2)
b) 40

c)
|xi |Fi |fi |
|3 |2 |0,05 |
|4 |5 |0,125 |
|5 |12 |0,3 |
|6 |10 |0,25 |
|7 |8 |0,2|
|8 |3 |0,075 |
| |40 |1 |

d)
|xi |Fi |Fac |
|3 |2 |2 |
|4 |5 |7 |
|5 |12 |19 |
|6 |10 |29 |
|7 |8 |37 |
|8 |3|40 |
| |40 | |
| | | |
| | | |

e)

|xi |Fi |fi |fiac |
|3 |2 |0,05 |0,05 |
|4 |5 |0,125 |0,175 |
|5 |12 |0,3 |0,475 |
|6|10 |0,25 |0,725 |
|7 |8 |0,2 |0,925 |
|8 |3 |0,075 |1 |
| |40 |1 | |

f)

3)
a) 15
b) 46
c) 20

4)

Classes 4: 6 l- 8
Classes 7: 12 l- 14

Xi 2: 3
Xi 5: 9
Xi 6: 11
Xi 8: 15

fi 3: 18
fi 6: 11
fi 8: 7
(= 100

Fi 1: 4Fi 2: 12
Fi 4: 57
Fi 8: 100

Fri 2: 0,08
Fri 5: 0,15
Fri 6: 0,11
(= 1

5)

A:
a) 5,1
b) (5+5)/2 = 5
c) Mo = 6
d) ( |2-5,1|+|2-5,1|+|3-5,1|+|5-5,1|+|5-5,1|+|5-5,1|+|6-5,1|+|6-5,1|+|8-5,1|+|9-5,1| )/ 10=
(3,1+3,1+2,1+0,1+0,1+0,1+0,9+0,9+2,9+3,9)/10=
= 1,72
e) [(2-5,1)²+(2-5,1)²+(3-5,1)²+(5-5,1)²+(5-5,1)²+(5-5,1)²+(6-5,1)²+(6-5,1)²+(8-5,1)²+(9-5,1)²]/ (10-1)=
48,9/9= 5,43
f)2,33

B:
a) 11
b) 9
c) Mo = 7
d) ( |2-11|+|7-11|+|7-11|+|7-11|+|9-11|+|12-11|+|15-11|+|20-11|+|20-11| ) / 9 =
(9+4+4+4+2+1+4+9+9)/9=
46/9 = 5,11
e) [ (2-11)²+(7-11)²+(7-11)²+(7-11)²+(9-11)²+(12-11)²+(15-11)²+(20-11)²+(20-11)² ] / (9-1) =
(81+16+16+16+4+1+16+81+81)/8= 38,87
f)6,23

C:
a) 49,8
b) 49,5
c) sem moda
d) ( |48,7-49,8|+|48,9-49,8|+|49,5-49,8|+|50,3-49,8|+|51,6-49,8| )/ 5...