Ep Eep

entrega Estaleiro Rio Grande – ERG (RS) 3 Navio-sonda Keppel FELS Brasil S/A– BRASFELS (RJ) 6 Semissubmersível 2016/17/18/19 Estaleiro Atlântico Sul – EAS (PE) 7 Navio-sonda 2016/17/18/19 Estaleiro Enseada Paraguaçu – EEP (BA) 6 Navio-sonda 2016/17/18/19/20 Estaleiro Jurong Aracruz – AJA (ES) 7 Navio-sonda 2016/17/19/20 Total de sondas 2016/17/18 29 Fonte: Petrobras; Sete Brasil Participações S/A; Sinaval. Elaboração…

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the D.E. we find A0 = 1 and A1 = 0. Hence, y = c1cost + c2sint + t. Applying the I.C., we obtain y = t. For t > p we have y≤ + y = pep-t so the form for Y(t) is Y(t) = Eep-t . Substituting Y(t) p-t p-t in the D.E., we obtain Ee + Ee = pep-t so E = p/2. Hence the general solution for t > p is Y = D1cost + D2sint + (p/2)ep-t . If y and y¢ are to be continuous at t = p, then the solutions and their derivatives for t £ p and t > p must have the same value at t = p.…